2026-10-08 02:20:19 +08:00
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<?php
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/**
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* 名册标签(v28 用户 2026-10-07 第 5 条)。
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*
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* 用户原话:「名册的分组,用下来不太好,我感觉应该改成打标签,就是说,一个人,
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* 他可能并不是只在一个分组,例如,他既是我的小学同学,又是我的初中同学,
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* 就没法分组,改成标签,似乎更合理。」
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*
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* 于是把「一人一组」换成「一人多标签」。三条关键设计:
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*
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* ① **每个人一份**(`owner_id`)—— 与 person_roster 同口径。
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* 我给他打「小学同学」,不该让全家的名册都多出这个标签;
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* 而且同一个人在我这儿是「球友」、在我妈那儿是「外甥」,本来就该各说各的。
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*
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* ② **标签词直接存字符串,不建标签表** —— 与笔记模块同一条轻量取舍。
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* 建一张标签表就要处理"改名后历史怎么办""两个标签合并",那是重型知识库才值
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* 的复杂度;这里标签就是"随手打的词",靠 GROUP BY 现算完事。
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*
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* ③ **不动 person_roster.group_id** —— 那一列是 vCard CATEGORIES 与老代码的读点,
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* 删掉会让"没跟上升级"的地方静默少一个字段。旧分组值已在 Schema 里
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* 一次性迁成同名标签(幂等),之后两边各走各的:新界面只认标签。
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*/
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declare(strict_types=1);
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namespace App;
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final class PersonTag
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{
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/** 标签长度与数量上限(挡住"把一句话当标签") */
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public const MAX_LEN = 24;
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public const MAX_EACH = 12;
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/**
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* 我的名册里每个人的标签:person_id => [tag, tag, ...]
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*
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* 一次取完(列表页要整页渲染),不做 N+1 —— 名册上千人时那是致命的。
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*/
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public static function mapFor(int $familyId, int $ownerId): array
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{
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if ($familyId <= 0 || $ownerId <= 0) {
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return [];
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}
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$st = Database::get()->prepare(
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'SELECT person_id, tag FROM person_tags
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WHERE family_id = ? AND owner_id = ?
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ORDER BY person_id, position, id'
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);
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$st->execute([$familyId, $ownerId]);
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$out = [];
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foreach ($st->fetchAll() as $r) {
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$out[(int)$r['person_id']][] = (string)$r['tag'];
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}
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return $out;
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}
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/** 单个(详情/编辑页用) */
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public static function of(int $ownerId, int $personId): array
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{
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if ($ownerId <= 0 || $personId <= 0) {
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return [];
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}
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$st = Database::get()->prepare(
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'SELECT tag FROM person_tags WHERE owner_id = ? AND person_id = ?
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ORDER BY position, id'
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);
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$st->execute([$ownerId, $personId]);
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$out = [];
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foreach ($st->fetchAll() as $r) {
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$out[] = (string)$r['tag'];
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}
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return $out;
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}
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/**
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* 我用过的全部标签 + 各挂了几个(顶部筛选条用)。
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*
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* ⚠️ 只统计**我的名册里还在的人** —— 否则会出现"标签上写着 5 个,
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* 点进去只有 3 个"(另外 2 个已经被移出名册,标签行还在)。
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*/
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public static function cloud(int $familyId, int $ownerId): array
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{
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if ($familyId <= 0 || $ownerId <= 0) {
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return [];
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}
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$st = Database::get()->prepare(
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'SELECT t.tag, COUNT(*) AS n
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FROM person_tags t
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JOIN person_roster r ON r.owner_id = t.owner_id AND r.person_id = t.person_id
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WHERE t.family_id = ? AND t.owner_id = ?
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GROUP BY t.tag
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ORDER BY n DESC, t.tag ASC'
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);
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$st->execute([$familyId, $ownerId]);
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return $st->fetchAll();
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}
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2026-10-17 00:15:06 +08:00
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/**
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* 打标签时的**候选词**(名册卡片浮层 / 编辑页 / 新增页都用它)。
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*
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* 🔴 v54(用户 2026-10-16 第 2 条)—— 这条是本次改动的核心。
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* 用户原话:「现在名册里面给人打标签的时候,**这个标签数据是从哪读出来的**呀?
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* 在这个名册的设置页面,有很多分组,现在还叫分组。但是打标签的时候,
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* **却不是从这些分组里读出来的**。所以现在应该在这个设置页面,不应该再叫
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* 「名册分组」了吧?应该叫「名册标签」,是不是?**应该从这里面把所有标签都读出来**吧?
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* 但是现在标签里面却只有几个,也不知道是从哪儿读出来的。」
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*
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* **真根因(用户观察得完全正确)**:
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* · 设置页显示的词表来自 `person_groups`(**分组表**,管理员/我维护的词);
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* · 打标签的候选来自 `cloud()`(**你已经打过的词**,现算的);
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* ⇒ 两边**根本不是一个数据源** —— 所以"设置里列着一堆、打标签时却只有几个"。
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*
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* ⇒ 合并两者,**并集**:
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* · 词表(`PersonGroup::orderFor` = 公共同我的)在前 —— 这是用户说的
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* "应该从这里面把所有标签都读出来";**还没用过**的词也要能一点就打上,
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* 这正是"词表"相对于"用过的词"的价值(否则新标签永远得手打)。
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* · 用过的词补在后面(词表里没收录、但历史打过的,不能凭空消失)。
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*
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* ⚠️ 只返回**词**(`array_column(...,'tag')` 那种扁平字符串列表),
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* 与既有 `tagChoices` 的消费方(模板 `foreach` 出 checkbox)契约一致 ——
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* 不返回 cloud 那种 `[['tag'=>..,'n'=>..]]`,否则调用点全要改。
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* ⚠️ 那个 `suggest()` 已被它取代(原名容易让人以为是"按人气排序的联想词",
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* 而实际需求是"设置里配的 + 用过的"并集)—— 保留一个没用处的旧口径
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* 只会让下一个人继续从 `cloud()` 读、把用户这条需求又绕过一遍。
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*
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* @return array<int,string>
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*/
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public static function choices(int $familyId, int $ownerId, int $limit = 60): array
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2026-10-08 02:20:19 +08:00
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{
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2026-10-17 00:15:06 +08:00
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if ($familyId <= 0 || $ownerId <= 0) {
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return [];
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}
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2026-10-08 02:20:19 +08:00
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$out = [];
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2026-10-17 00:15:06 +08:00
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// ① 词表(设置页「名册标签」里配的那些:公共同我的,带顺序)
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foreach (PersonGroup::orderFor($familyId, $ownerId) as $g) {
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$nm = trim((string)($g['name'] ?? ''));
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if ($nm !== '' && !in_array($nm, $out, true)) {
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$out[] = $nm;
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2026-10-08 02:20:19 +08:00
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}
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}
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2026-10-17 00:15:06 +08:00
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// ② 我已经打过的词(词表里没收录的补上;按人气降序)
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foreach (self::cloud($familyId, $ownerId) as $r) {
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$t = (string)($r['tag'] ?? '');
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if ($t !== '' && !in_array($t, $out, true)) {
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$out[] = $t;
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}
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}
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return array_slice($out, 0, max(1, $limit));
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2026-10-08 02:20:19 +08:00
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}
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/**
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* 整组替换某人的标签(名册卡片上改标签就用它)。
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*
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* 为什么是"整组替换"而不是逐个增删:界面是一次提交一整套标签的,
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* 逐个 diff 反而要处理"哪些是新增/哪些是删除",代码多且容易漏。
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* 标签没有历史价值,全量重写最简单可靠。
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*
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* @param array|string $raw 数组,或一段用空格/逗号分隔的标签
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* @return array<int,string> 归一后真正写进去的标签(调用方可以回显)
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*/
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public static function setFor(int $familyId, int $ownerId, int $personId, $raw): array
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{
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if ($familyId <= 0 || $ownerId <= 0 || $personId <= 0) {
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return [];
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}
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$tags = self::clean($raw);
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$db = Database::get();
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$db->prepare('DELETE FROM person_tags WHERE owner_id = ? AND person_id = ?')
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->execute([$ownerId, $personId]);
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if (!$tags) {
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return [];
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}
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$st = $db->prepare(
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'INSERT INTO person_tags (family_id, owner_id, person_id, tag, position)
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VALUES (?,?,?,?,?)'
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);
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$pos = 10;
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foreach ($tags as $t) {
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$st->execute([$familyId, $ownerId, $personId, $t, $pos]);
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$pos += 10;
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}
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return $tags;
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}
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/** 删某人时把他的标签一起删(persons 外键也会级联,这里显式一次更稳)。 */
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public static function forgetPerson(int $personId): void
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{
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if ($personId <= 0) {
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return;
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}
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Database::get()->prepare('DELETE FROM person_tags WHERE person_id = ?')->execute([$personId]);
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}
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2026-10-17 00:15:06 +08:00
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/**
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* 给某人**追加**一个标签(已存在则不重复)。
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*
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* 🔴 v54(用户 2026-10-16 第 2 条):挑人 / 导入联系人时要用它。
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* 为什么必须是"追加"而不是 `setFor()`(整组替换):
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* `setFor` 会**先 DELETE 再 INSERT** —— 用在这里会把那些人
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* **原有**的标签一起清掉。而这两个入口的语义是"顺手给新人打一个标签",
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* 不是"把他们的标签改成这一个"。这种"用整组替换去做追加"的错,
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* 症状是"用一次导入,别人身上原有的标签全没了",而且很难联想到原因。
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*
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* ⚠️ 靠 `uk_pt`(owner_id, person_id, tag 三列唯一)保证幂等:
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* 重复打同一个词会 `duplicate`,这里用 INSERT IGNORE 吞掉,不报错。
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* @return bool 这次真的插进去了吗(已存在 = false)
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*/
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public static function addOne(int $familyId, int $ownerId, int $personId, string $tag): bool
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{
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$one = self::clean($tag);
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if ($familyId <= 0 || $ownerId <= 0 || $personId <= 0 || !$one) {
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return false;
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}
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$st = Database::get()->prepare(
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'INSERT IGNORE INTO person_tags (family_id, owner_id, person_id, tag, position)
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VALUES (?,?,?,?,?)'
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);
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$st->execute([$familyId, $ownerId, $personId, $one[0], 100]);
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return $st->rowCount() > 0;
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}
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2026-10-08 02:20:19 +08:00
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/**
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* 标签归一:`#小学同学` / `小学同学 ` / `小学,同学` 都要变成干净的词。
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*
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* 与 Note::cleanTags 同一套规则(去 `#`、去空白、去重、限长限数)——
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* 两处各写一份迟早不一致(用户在笔记里能打 `#`,在名册里却打不了,最恼人)。
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*/
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public static function clean($raw): array
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{
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$list = [];
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if (is_array($raw)) {
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$list = $raw;
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} elseif (is_string($raw)) {
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$list = preg_split('/[\s,,]+/u', $raw) ?: [];
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}
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$out = [];
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foreach ($list as $t) {
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$t = trim((string)$t);
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$t = ltrim($t, '#');
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// 空白与 `#` 都不能出现在标签内部(它们是分隔符)
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$t = (string)preg_replace('/[\s#]+/u', '', $t);
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if ($t === '') {
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continue;
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}
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$t = mb_substr($t, 0, self::MAX_LEN, 'UTF-8');
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if (!in_array($t, $out, true)) {
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$out[] = $t;
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}
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if (count($out) >= self::MAX_EACH) {
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break;
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}
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}
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return $out;
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}
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}
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